MathLabs

Problem 6

Let SS be a square with side length 100100. Let LL be a simple closed polygonal path inside SS, composed of segments A0A1,A1A2,…,An−1AnA_0A_1,A_1A_2,\ldots,A_{n-1}A_n with A0=AnA_0=A_n. Suppose that every point PP on the boundary of SS is at distance at most 1/21/2 from some point of LL. Prove that there are points X,YX,Y of LL whose distance is at most 11 and for which the length of the part of LL between XX and YY is at least 198198.
Step 4 of 5: Make the two points close
In plain words

Both points lie in the same half-unit neighborhood of X′X', so they are at most one unit apart.

XY≤XX′+X′Y≤12+12=1XY\le XX'+X'Y\le\frac12+\frac12=1
Detailed analysis

Choose YY on L2L_2 within 1/21/2 of X′X'. Since XX is within 1/21/2 of X′X' by definition, the triangle inequality gives XY≤1XY\le1.