MathLabs

Problem 2

Let AA be one of the two distinct intersection points of unequal coplanar circles C1,C2C_1,C_2 with centers O1,O2O_1,O_2. One common tangent touches them at P1,P2P_1,P_2, and the other at Q1,Q2Q_1,Q_2. Let M1,M2M_1,M_2 be the midpoints of P1Q1,P2Q2P_1Q_1,P_2Q_2. Prove that ∠O1AO2=∠M1AM2\angle O_1AO_2=\angle M_1AM_2.
Step 1 of 5: Introduce the homothety center SS
S=P1P2∩Q1Q2,S∈O1O2S=P_1P_2\cap Q_1Q_2,\qquad S\in O_1O_2
Detailed analysis

The two common tangents meet at SS. The center line of two nonconcentric circles passes through the external homothety center, so S,O1,O2S,O_1,O_2 are collinear.