MathLabs

Problem 3

Given points OO and AA in the plane, every point is colored with one of a finite number of colors. For a point XX, let C(X)C(X) be the circle centered at OO with radius OX+∠AOXOXOX+\frac{\angle AOX}{OX}, where ∠AOX\angle AOX is measured in radians in [0,2π)\left[0,2\pi\right). Prove that there is a point XX, not on OAOA, such that the color of XX appears on the circumference of C(X)C(X).
Step 3 of 6: Build the point matrix
In plain words

The matrix is a bookkeeping device: moving down one row and right one column always selects a circle farther out by the sum of the two indices.

M=(xi,j)i,j≥1,xi,j∈Ci,C(xi,j)=Ci+jM=(x_{i,j})_{i,j\ge1},\quad x_{i,j}\in\mathcal C_i,\quad C(x_{i,j})=\mathcal C_{i+j}
Detailed analysis

Arrange all these points in an infinite matrix, with row ii consisting of points on Ci\mathcal C_i. The entry in row ii, column jj points to the circle indexed by i+ji+j.