MathLabs

Problem 3

Given points OO and AA in the plane, every point is colored with one of a finite number of colors. For a point XX, let C(X)C(X) be the circle centered at OO with radius OX+∠AOXOXOX+\frac{\angle AOX}{OX}, where ∠AOX\angle AOX is measured in radians in [0,2π)\left[0,2\pi\right). Prove that there is a point XX, not on OAOA, such that the color of XX appears on the circumference of C(X)C(X).
Step 4 of 6: Use the first repeated color
In plain words

A repeated color on a source point bans that color from its target circle, otherwise the theorem would already be finished.

x1,jk all have color c1 ⟹ c1 is absent from C1+jkx_{1,j_k}\text{ all have color }c_1\ \Longrightarrow\ c_1\text{ is absent from }\mathcal C_{1+j_k}
Detailed analysis

Assume the desired point does not exist. Since the first row has finitely many colors, some color c1c_1 occurs at infinitely many entries x1,jkx_{1,j_k}. If c1c_1 occurred anywhere on C1+jk\mathcal C_{1+j_k}, that entry itself would be a desired point; hence c1c_1 is forbidden on every such circle.