MathLabs

Problem 5

Given n0>1n_0>1, players A and B choose integers alternately. Knowing n2kn_{2k}, A chooses n2k+1n_{2k+1} with n2k≤n2k+1≤n2k2n_{2k}\le n_{2k+1}\le n_{2k}^2. Knowing n2k+1n_{2k+1}, B chooses n2k+2n_{2k+2} such that n2k+1/n2k+2=prn_{2k+1}/n_{2k+2}=p^r for a prime pp and integer r≥1r\ge1. A wins by choosing 19901990, and B wins by choosing 11. Classify the initial values according to which player has a winning strategy or neither does.
Step 5 of 6: The position 6 reduces to 30
n0=6:n1=30 is A’s only nonlosing moven_0=6:\quad n_1=30\text{ is A's only nonlosing move}
Detailed analysis

For n0=6, choices through 29 lose by the preceding bounds. If A chooses 31,32,33,34,35, or 36, B can choose respectively 1,1,3,2,5,4. Thus A's only nonlosing move is 30. From 30, B can choose 6,10, or 15; choosing 10 or 15 loses by the preceding analysis, so optimal B chooses 6.