MathLabs

Problem 6

Prove that there exists a convex 1990-gon whose angles are all equal and whose side lengths are 12,22,…,199021^2,2^2,\ldots,1990^2 in some order.
Step 1 of 4: Encode the equiangular sides as complex vectors
ω=e2πi/1990,vi,j,k=r(i,j,k)2(−1)iajbk\omega=e^{2\pi i/1990},\qquad v_{i,j,k}=r(i,j,k)^2(-1)^ia^jb^k
Detailed analysis

Let ω\omega be a primitive 1990th root of unity. We will assign the length r(i,j,k)2r(i,j,k)^2 to the direction (−1)iajbk(-1)^ia^jb^k. These directions are precisely the 1990 successive directions whose arguments increase by 2π/19902\pi/1990. If the vector sum is zero, the corresponding positive side vectors close to form an equiangular polygon; the constant positive turn makes it convex.