MathLabs

Problem 6

Given any real number a>1, construct a bounded infinite sequence x0,x1,x2,…x_0,x_1,x_2,\ldots such that ∣xn−xm∣ ∣n−m∣a≥1|x_n-x_m|\,|n-m|^a\ge1 for every pair of distinct n,m.
Step 4 of 4: Bound the tail and finish
c∣xn−xm∣>ctk,∣xn−xm∣ ∣n−m∣a>ctk2ak=1c|x_n-x_m|>ct^k,\qquad |x_n-x_m|\,|n-m|^a>ct^k2^{ak}=1
Detailed analysis

At the first differing bit, the contribution to c times the difference has magnitude t^k; the remaining tail is bounded below by minus the sum from i=k+1 onward, namely minus t^(k+1)/(1−t). Thus c|x_n−x_m| is greater than t^k(1−t/(1−t))=ct^k. Multiplying by |n−m|^a≥2^(ak) gives a product greater than t^k2^(ak)=1, as required.