MathLabs

International Mathematical Olympiad · 1997

Problems

  1. Problem 1In the plane, points with integer coordinates are vertices of unit squares, colored alternately black and white as on a chessboard. For positive integers m,n m,n , consider a right triangle with integer-coordinate vertices and legs of lengths m,n m,n along square edges. Let S1 S_1 be the black area and S2 S_2 the white area. Define f(m,n)=∣S1−S2∣ f(m,n)=|S_1-S_2|. (a) Calculate f(m,n) f(m,n) when m,n m,n are both even or both odd. (b) Prove f(m,n)≤max⁡(m,n)/2 f(m,n)\le\max(m,n)/2. (c) Show that no constant C C satisfies f(m,n)<C f(m,n)<C for all m,n m,n .Solutions: 1
  2. Problem 2The angle at A A is the smallest angle in triangle ABC ABC . The points B,C B,C divide its circumcircle into two arcs. Let U U be an interior point of the arc BC BC not containing A A . The perpendicular bisectors of AB AB and AC AC meet line AU AU at V V and W W , respectively. The lines BV BV and CW CW meet at T T . Show that AU=TB+TC AU=TB+TC .Solutions: 1
  3. Problem 3Let x1,x2,…,xn x_1,x_2,\ldots,x_n be real numbers satisfying ∣x1+x2+⋯+xn∣=1|x_1+x_2+\cdots+x_n|=1 and ∣xi∣≤(n+1)/2|x_i|\le(n+1)/2 for every i i . Show that there is a permutation y1,…,yn y_1,\ldots,y_n of the xi x_i such that ∣y1+2y2+⋯+nyn∣≤(n+1)/2|y_1+2y_2+\cdots+ny_n|\le(n+1)/2.Solutions: 1
  4. Problem 4An n×n n\times n matrix whose entries belong to S={1,2,…,2n−1} S=\{1,2,\ldots,2n-1\} is called a silver matrix if, for each i i , the i i th row together with the i i th column contains all elements of S S . Show that (a) there is no silver matrix for n=1997 n=1997; (b) silver matrices exist for infinitely many n n .Solutions: 1
  5. Problem 5Find all pairs (a,b)(a,b) of positive integers satisfying ab2=ba a^{b^2}=b^a .Solutions: 1
  6. Problem 6For each positive integer N N , let f(N) f(N) be the number of ways to represent N N as a sum of powers of 22 with non-negative integer exponents; order of summands is ignored. For example, f(4)=4 f(4)=4. Prove that for every integer n≥3 n\ge3, 2n2/4<f(2n)<2n2/22^{n^2/4}<f(2^n)<2^{n^2/2}.Solutions: 1