MathLabs

Problem 6

Determine the least possible value of f(1998) f(1998), where f:N→N f:\mathbb{N}\to\mathbb{N} is a function such that for all m,n∈N m,n\in\mathbb{N}, f(n2f(m))=m(f(n))2. f\left(n^{2}f(m)\right)=m\left(f(n)\right)^{2}.
Step 1 of 6: Extract the first identities
In plain words

Special substitutions reveal the scaling constant.

f(kt2)=f(t)2,f(f(t))=k2t,k=f(1)f(kt^2)=f(t)^2,\quad f(f(t))=k^2t,\quad k=f(1)
Detailed analysis

Setting m=1 m=1 gives f(kt2)=f(t)2 f(kt^2)=f(t)^2, while setting n=1 n=1 gives f(f(t))=k2t f(f(t))=k^2t . Applying these identities to t t and kt kt yields f(kt)=kf(t) f(kt)=kf(t).