MathLabs

Problem 5

Two circles G1 G_1 and G2 G_2 are contained inside the circle G G , and are tangent to G G at the distinct points M M and N N , respectively. G1 G_1 passes through the center of G2 G_2. The line passing through the two points of intersection of G1 G_1 and G2 G_2 meets G G at A A and B B . The lines MA MA and MB MB meet G1 G_1 at C C and D D , respectively. Prove that CD CD is tangent to G2 G_2.
Step 3 of 6: Locate the chord on the centers line
In plain words

The common chord’s projection is fixed by the radii.

O2V=r222r1O_2V=\frac{r_2^2}{2r_1}
Detailed analysis

Let V=AB∩O1O2 V=AB\cap O_1O_2. The standard intersecting-chords/homothety computation for two circles with O2∈G1 O_2\in G_1 gives O2V=r22/(2r1) O_2V=r_2^2/(2r_1). This is obtained by taking an intersection point of G1,G2 G_1,G_2 and using the similar triangles formed by the midpoint of the corresponding chord.