MathLabs

Problem 2

Let a,b,c a,b,c be positive real numbers with abc=1 abc=1. Prove that (a−1+1b)(b−1+1c)(c−1+1a)≤1(a-1+\frac1b)(b-1+\frac1c)(c-1+\frac1a)\le 1.
Step 2 of 4: Rewrite
(x−y+z)(x+y−z)(−x+y+z)xyz.\frac{(x-y+z)(x+y-z)(-x+y+z)}{xyz}.
Detailed analysis

Substitution gives this product.