MathLabs

Problem 3

Let n≥2 n\ge2 be a positive integer. Initially there are n n fleas on a horizontal line, not all at the same point. For a positive real number λ\lambda , a move chooses fleas at A A and B B with A A to the left of B B , and lets the flea at A A jump to C C to the right of B B so that BC=λAB BC=\lambda AB . Determine all λ\lambda such that, for every point M M and every initial position, a finite sequence of moves puts all fleas to the right of M M .
Step 2 of 4: Prove sufficiency at and above the threshold
In plain words

Preserve the minimum gap.

λ≥1n−1\lambda\ge\frac1{n-1}
Detailed analysis

Now assume λ≥1/(n−1)\lambda\ge1/(n-1). Let dd be the smallest gap and D=xn−x1D=x_n-x_1. Since DD is the sum of n−1n-1 gaps, D≥(n−1)dD\ge(n-1)d, so λD≥d\lambda D\ge d. Move the leftmost flea over the rightmost one; the new minimum gap is at least dd.