MathLabs

Problem 4

Let n≥3n\ge 3 be an integer and t1,t2,…,tnt_1,t_2,\dots,t_n positive real numbers such that n2+1>(t1+t2+⋯+tn)(1t1+1t2+⋯+1tn).n^2+1 > (t_1+t_2+\cdots+t_n)\left(\frac{1}{t_1}+\frac{1}{t_2}+\cdots+\frac{1}{t_n}\right). Show that ti,tj,tkt_i,t_j,t_k are the lengths of the sides of a triangle for all i,j,ki,j,k with 1≤i<j<k≤n1\le i<j<k\le n.
Step 2 of 4: Bound the non-triple pairs by AM–GM
trts+tstr≥2 for the (n2)−3 pairs outside {1,2,3}  ⟹  (ab+ba)+(bc+cb)+(ca+ac)<7\frac{t_r}{t_s}+\frac{t_s}{t_r}\ge2\text{ for the }\binom{n}{2}-3\text{ pairs outside }\{1,2,3\}\implies \left(\frac{a}{b}+\frac{b}{a}\right)+\left(\frac{b}{c}+\frac{c}{b}\right)+\left(\frac{c}{a}+\frac{a}{c}\right)<7
Detailed analysis

For each of the (n2)−3\binom{n}{2}-3 pairs (r,s)(r,s) not contained in {1,2,3}\{1,2,3\}, AM–GM gives tr/ts+ts/tr≥2t_r/t_s+t_s/t_r\ge 2, so those pairs contribute at least 2((n2)−3)=n(n−1)−62\bigl(\binom{n}{2}-3\bigr)=n(n-1)-6. Subtracting this and the diagonal nn from n2+1n^2+1 leaves (a/b+b/a)+(b/c+c/b)+(c/a+a/c)<7(a/b+b/a)+(b/c+c/b)+(c/a+a/c)<7 for the three pairs inside {1,2,3}\{1,2,3\}.