MathLabs

Problem 1

Six points are chosen on the sides of an equilateral triangle ABCABC: A1,A2A_1, A_2 on BCBC, B1,B2B_1, B_2 on CACA and C1,C2C_1, C_2 on ABAB, such that they are the vertices of a convex hexagon A1A2B1B2C1C2A_1A_2B_1B_2C_1C_2 with equal side lengths. Prove that the lines A1B2A_1B_2, B1C2B_1C_2 and C1A2C_1A_2 are concurrent.
Step 1 of 6: Close up the hexagon
In plain words

Walking all the way around a closed hexagon and back to the start means the six edge vectors must cancel out.

A1A2→+A2B1→+B1B2→+B2C1→+C1C2→+C2A1→=0⃗\overrightarrow{A_1A_2}+\overrightarrow{A_2B_1}+\overrightarrow{B_1B_2}+\overrightarrow{B_2C_1}+\overrightarrow{C_1C_2}+\overrightarrow{C_2A_1}=\vec0
Detailed analysis

The six points, taken in this cyclic order, form a closed hexagon, so the sum of its six directed edges is the zero vector.