MathLabs

Problem 1

Six points are chosen on the sides of an equilateral triangle ABCABC: A1,A2A_1, A_2 on BCBC, B1,B2B_1, B_2 on CACA and C1,C2C_1, C_2 on ABAB, such that they are the vertices of a convex hexagon A1A2B1B2C1C2A_1A_2B_1B_2C_1C_2 with equal side lengths. Prove that the lines A1B2A_1B_2, B1C2B_1C_2 and C1A2C_1A_2 are concurrent.
Step 2 of 6: Three equal-length sides cancel
In plain words

Equal-length vectors pointing along the three directions of an equilateral triangle, each rotated 120∘120^\circ from the last, always add to zero.

A1A2→+B1B2→+C1C2→=0⃗\overrightarrow{A_1A_2}+\overrightarrow{B_1B_2}+\overrightarrow{C_1C_2}=\vec0
Detailed analysis

The segments A1A2A_1A_2, B1B2B_1B_2, C1C2C_1C_2 all have the same length (the hexagon's common side length) and lie along BCBC, CACA, ABAB respectively, directions that differ by successive 120∘120^\circ rotations around the equilateral triangle ABCABC. Three equal-length vectors related by 120∘120^\circ rotations sum to 0⃗\vec0.