MathLabs

Problem 1

Six points are chosen on the sides of an equilateral triangle ABCABC: A1,A2A_1, A_2 on BCBC, B1,B2B_1, B_2 on CACA and C1,C2C_1, C_2 on ABAB, such that they are the vertices of a convex hexagon A1A2B1B2C1C2A_1A_2B_1B_2C_1C_2 with equal side lengths. Prove that the lines A1B2A_1B_2, B1C2B_1C_2 and C1A2C_1A_2 are concurrent.
Step 5 of 6: One vertex, two equal chords
In plain words

Chasing angles around the circle through A1,B1,C,DA_1,B_1,C,D turns the equal inscribed angles into two congruent triangles at A2A_2.

A2B2=A2C2A_2B_2=A_2C_2
Detailed analysis

Equal inscribed angles in that circle give ∠CA1D=∠CB1D\angle CA_1D=\angle CB_1D, hence ∠C2A1A2=∠A2B1B2\angle C_2A_1A_2=\angle A_2B_1B_2. Together with the hexagon's equal side lengths this makes triangles C2A1A2C_2A_1A_2 and A2B1B2A_2B_1B_2 congruent, so A2C2=A2B2A_2C_2=A_2B_2: vertex A2A_2 is equidistant from B2B_2 and C2C_2.