MathLabs

Problem 5

Let P(x)P(x) be a polynomial of degree n>1n>1 with integer coefficients, and let kk be a positive integer. Define Q(x)=P(P(…P(x)…))Q(x)=P(P(\ldots P(x)\ldots)), where PP occurs kk times. Prove that there are at most nn integers tt such that Q(t)=tQ(t)=t.
Step 5 of 8: Compare two 2-cycles by divisibility
∣α−a∣=∣β−b∣,∣α−b∣=∣β−a∣|\alpha-a|=|\beta-b|,\qquad |\alpha-b|=|\beta-a|
Detailed analysis

Fix one genuine 2-cycle P(a)=bP(a)=b, P(b)=aP(b)=a. For another fixed point P2(α)=αP^2(\alpha)=\alpha, write β=P(α)\beta=P(\alpha), so P(β)=αP(\beta)=\alpha. Applying the divisibility lemma to (α,a)(\alpha,a) and (β,b)(\beta,b) in both directions shows that α−a\alpha-a and β−b\beta-b divide each other, and likewise α−b\alpha-b and β−a\beta-a divide each other. Hence the displayed absolute-value equalities hold.