Problem 6
Find all positive integers for which there exist nonnegative integers such that .
Step 4 of 4: Check the five base sequences
In plain words
The bases cover lengths 1,5,9,13,17; the odd-to-even step then covers the adjacent even lengths.
Detailed analysis
Direct substitution verifies feasibility for the exponent lists of lengths displayed in the formula. The odd-to-even step gives lengths , and the 11-point extension gives every later length ; applying the odd-to-even step again gives the corresponding lengths. Hence every is attainable, matching the necessary condition.