MathLabs

Problem 3

Let the excircle of triangle ABCABC opposite the vertex AA be tangent to the side BCBC at the point A1A_1. Define the points B1B_1 on CACA and C1C_1 on ABAB analogously, using the excircles opposite BB and CC, respectively. Suppose that the circumcentre of triangle A1B1C1A_1B_1C_1 lies on the circumcircle of triangle ABCABC. Prove that triangle ABCABC is right-angled.
Step 2 of 5: Identify the circumcentre with X
Q=XQ=X
Detailed analysis

Let QQ be the circumcentre of A1B1C1A_1B_1C_1. The hypothesis puts QQ on Ω\Omega. By the cyclic symmetry of the construction, we may choose the labeling so that ∠B1A1C1>90∘\angle B_1A_1C_1>90^\circ. Then AA and the arc-midpoint point XX lie on the same side of B1C1B_1C_1. Since QQ lies on the perpendicular bisector of B1C1B_1C_1 and also on Ω\Omega, the configuration forces Q=XQ=X.