MathLabs

Problem 6

The sequence a1,a2,…a_1,a_2,\dots of integers satisfies the conditions: (i) 1≤aj≤20151\le a_j\le 2015 for all j≥1j\ge1; (ii) k+ak≠ℓ+aℓk+a_k\ne \ell+a_\ell for all 1≤k<ℓ1\le k<\ell. Prove that there exist two positive integers bb and NN for which ∣∑j=m+1n(aj−b)∣≤10072\left|\sum_{j=m+1}^{n}(a_j-b)\right|\le 1007^2 for all integers mm and nn such that n>m≥Nn>m\ge N.
Step 5 of 6: Bounding the overshoot sum at a fixed boundary
In plain words

The bb chains next-exit points past tt must be distinct positive integers no larger than 20152015, so their sum is squeezed between the bb smallest and bb largest such values.

1+2+⋯+b ≤ ∑chain c(min⁡{x>t:x∈c}−t) ≤ 2015+2014+⋯+(2015−b+1)1+2+\dots+b\ \le\ \sum_{\text{chain }c}\big(\min\{x>t:x\in c\}-t\big)\ \le\ 2015+2014+\dots+(2015-b+1)
Detailed analysis

Fix a boundary tt (=m=m or nn) with t≥Nt\ge N. For each of the bb chains, min⁡{x>t:x∈c}−t\min\{x>t:x\in c\}-t is a positive integer at most 20152015 (consecutive elements of one chain differ by at most 20152015), and these bb overshoot values are pairwise distinct across the bb chains, since a given point xx belongs to only one chain. Hence their sum lies between the sum of the bb smallest possible distinct positive values, 1+2+⋯+b1+2+\cdots+b, and the sum of the bb largest possible values not exceeding 20152015, namely 2015+2014+⋯+(2015−b+1)2015+2014+\cdots+(2015-b+1).