MathLabs

Problem 3

A hunter and an invisible rabbit play a game in the Euclidean plane. The rabbit's starting point, A0A_0, and the hunter's starting point, B0B_0, are the same. After n−1n-1 rounds of the game, the rabbit is at An−1A_{n-1} and the hunter is at Bn−1B_{n-1}. In the nnth round, three things occur in order: (i) the rabbit moves invisibly to a point AnA_n such that the distance between An−1A_{n-1} and AnA_n is exactly 11; (ii) a tracking device reports a point PnP_n to the hunter, with the only guarantee that the distance between PnP_n and AnA_n is at most 11; (iii) the hunter moves visibly to a point BnB_n such that the distance between Bn−1B_{n-1} and BnB_n is exactly 11. Is it always possible, no matter how the rabbit moves and no matter what points are reported by the tracking device, for the hunter to choose her moves so that after 10910^9 rounds she can ensure that the distance between her and the rabbit is at most 100100?
Step 4 of 9: The hunter cannot identify the side
H∗∈r,∣HH∗∣=200,∣H∗R∣=200−dH^*\in r,\qquad |HH^*|=200,\qquad |H^*R|=200-d
Detailed analysis

Let H∗H^* be the point on rr reached by going 200200 units from HH through RR. Every point QQ reachable by the hunter after 200200 unit moves has projection on rr no farther in the direction from HH through RR than H∗H^*. Since d≥1d\ge1 while the small offset of YiY_i from the point 200200 units beyond RR is less than 1/4001/400, both destinations lie beyond H∗H^*. The reports are identical for the two routes, so the hunter follows the same path in both cases. Whichever side of rr the final QQ lies on, the destination on the opposite side is at least as far from QQ as H∗YiH^*Y_i. If QQ lies on rr, either destination has that lower bound. Thus the rabbit can choose a route with final distance at least y:=H∗Y1=H∗Y2y:=H^*Y_1=H^*Y_2.