MathLabs

Problem 3

A hunter and an invisible rabbit play a game in the Euclidean plane. The rabbit's starting point, A0A_0, and the hunter's starting point, B0B_0, are the same. After n−1n-1 rounds of the game, the rabbit is at An−1A_{n-1} and the hunter is at Bn−1B_{n-1}. In the nnth round, three things occur in order: (i) the rabbit moves invisibly to a point AnA_n such that the distance between An−1A_{n-1} and AnA_n is exactly 11; (ii) a tracking device reports a point PnP_n to the hunter, with the only guarantee that the distance between PnP_n and AnA_n is at most 11; (iii) the hunter moves visibly to a point BnB_n such that the distance between Bn−1B_{n-1} and BnB_n is exactly 11. Is it always possible, no matter how the rabbit moves and no matter what points are reported by the tracking device, for the hunter to choose her moves so that after 10910^9 rounds she can ensure that the distance between her and the rabbit is at most 100100?
Step 7 of 9: Each block increases squared distance
y2=d2+ε(400−2d)>d2+12y^2=d^2+\varepsilon(400-2d)>d^2+\frac12
Detailed analysis

Substitute ε2+1=400ε\varepsilon^2+1=400\varepsilon into y2=1+(d−ε)2y^2=1+(d-\varepsilon)^2 to get y2=d2+ε(400−2d)y^2=d^2+\varepsilon(400-2d). Because d≤100d\le100, we have 400−2d≥200400-2d\ge200, and because ε>1/400\varepsilon>1/400, it follows that y2>d2+1/2y^2>d^2+1/2. Thus, regardless of the hunter's moves, the rabbit can choose one of the indistinguishable routes so that after 200200 rounds the new squared distance is greater than the old one by 1/21/2.