Problem 6
An ordered pair of integers is called a primitive point if . Given a finite set of primitive points, prove that there exist a positive integer and integers such that for every , we have .
Step 6 of 8: Build the corrected polynomial
In plain words
The first term preserves old values, while the product correction vanishes there.
Detailed analysis
Let , which is an integer because . Define . Both summands are homogeneous of degree nU, so Q has integer coefficients and positive degree.