Problem 5
Let be an infinite sequence of positive integers. Suppose there is an integer such that, for every , the number is an integer. Prove that there is a positive integer such that for all .
Step 4 of 8: If a valuation reaches , it descends
Detailed analysis
Now suppose and put . If for some , induction gives and thereafter. Indeed, if the next valuation were below , the first and third terms of would have unequal valuations (the possible equality would force ), leaving a unique negative valuation; and if it exceeded the current one, the third term would be uniquely negative. Thus the integer sequence of valuations is eventually constant.