MathLabs

Problem 3

Let DD be an interior point of the acute triangle ABCABC with AB>ACAB>AC so that ∠DAB=∠CAD\angle DAB=\angle CAD. The point EE on the segment ACAC satisfies ∠ADE=∠BCD\angle ADE=\angle BCD, the point FF on the segment ABAB satisfies ∠FDA=∠DBC\angle FDA=\angle DBC, and the point XX on the line ACAC satisfies CX=BXCX=BX. Let O1O_1 and O2O_2 be the circumcenters of the triangles ADCADC and EXDEXD, respectively. Prove that the lines BCBC, EFEF, and O1O2O_1O_2 are concurrent.
Step 6 of 6: Conclude the concurrency
P∈BC∩EF∩O1O2P\in BC\cap EF\cap O_1O_2
Detailed analysis

By definition P∈BCP\in BC and P∈EFP\in EF, and the preceding step gives P∈O1O2P\in O_1O_2. Thus BCBC, EFEF, and O1O2O_1O_2 are concurrent at PP.