MathLabs

Problem 3

For each integer k≥2k\ge2, determine all infinite sequences of positive integers a1,a2,…a_1,a_2,\ldots for which there exists a polynomial PP of the form P(x)=xk+ck−1xk−1+⋯+c1x+c0P(x)=x^k+c_{k-1}x^{k-1}+\cdots+c_1x+c_0, where c0,c1,…,ck−1c_0,c_1,\ldots,c_{k-1} are non-negative integers, such that P(an)=an+1an+2⋯an+kP(a_n)=a_{n+1}a_{n+2}\cdots a_{n+k} for every integer n≥1n\ge1.
Step 1 of 6: Arithmetic progressions work
In plain words

If the terms increase by a fixed step d, the k terms right after a_n are simply a_n plus the first k multiples of d, so their product is a fixed polynomial evaluated at a_n.

an=a1+(n−1)d  ⟹  P(x)=∏j=1k(x+jd)a_n=a_1+(n-1)d\implies P(x)=\prod_{j=1}^k(x+jd)
Detailed analysis

If an=a1+(n−1)da_n=a_1+(n-1)d for an integer d≥0d\ge0, then an+1an+2⋯an+k=(an+d)(an+2d)⋯(an+kd)a_{n+1}a_{n+2}\cdots a_{n+k}=(a_n+d)(a_n+2d)\cdots(a_n+kd), so P(x)=(x+d)(x+2d)⋯(x+kd)P(x)=(x+d)(x+2d)\cdots(x+kd) works, and its coefficients besides the leading one are non-negative since d≥0d\ge0.