Problem 3
For each integer , determine all infinite sequences of positive integers for which there exists a polynomial of the form , where are non-negative integers, such that for every integer .
Step 2 of 6: A telescoping identity
In plain words
Writing the defining relation for two consecutive indices and dividing cancels most of the product, leaving a clean relationship between and .
Detailed analysis
The relation gives and . Dividing, all the shared factors cancel, leaving .