MathLabs

Problem 6

A function f:Q→Qf:\mathbb Q\to\mathbb Q is called aquaesulian if the following property holds: for every x,y∈Qx,y\in\mathbb Q, f(x+f(y))=f(x)+yf(x+f(y))=f(x)+y or f(f(x)+y)=x+f(y)f(f(x)+y)=x+f(y). Show that there exists an integer cc such that for any aquaesulian function ff there are at most cc different rational numbers of the form f(r)+f(−r)f(r)+f(-r) for some rational number rr, and find the smallest possible value of cc.
Step 4 of 5: A dichotomy from applying the property once more
In plain words

Feeding a cleverly chosen pair into the defining property and using injectivity splits every situation into exactly two clean outcomes, one of which pins down f(r) plus f(-r) as zero and the other of which expresses it in terms of f(f(s)) minus s.

s→r  ⟹  f(r)+f(−r)=0 or f(f(s))=s+f(r)+f(−r)s\to r\implies f(r)+f(-r)=0\ \text{or}\ f(f(s))=s+f(r)+f(-r)
Detailed analysis

Given s→rs\to r, apply the hypothesis to x=s+f(r)x=s+f(r) and y=−ry=-r: one of x→yx\to y or y→xy\to x holds. Direct computation of both sides using s→rs\to r and injectivity of ff (Step 3) shows that if x→yx\to y holds, then f(r)+f(−r)=0f(r)+f(-r)=0, while if y→xy\to x holds, then f(f(s))=s+f(r)+f(−r)f(f(s))=s+f(r)+f(-r).