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Open problem, Arithmetic and number theory, posed 1734

Irrationality of ζ(5) and odd zeta values

Open

Is ζ(5)=∑n=1∞1n5\zeta(5) = \sum_{n=1}^\infty \frac{1}{n^5} irrational? More generally, is ζ(2k+1)\zeta(2k+1) irrational (and transcendental) for every integer k≥2k \ge 2?

Research frontier as of 2026

As of 2026, ζ(3)\zeta(3) remains the only specific odd zeta value proved to be irrational, and it is still unknown whether ζ(3)\zeta(3) is transcendental or whether ζ(5)\zeta(5) is irrational. Refinements of the Ball–Rivoal and Zudilin hypergeometric constructions, together with Fischler–Sprang–Zudilin (2019) elimination techniques, have produced explicit lower bounds for the number of irrational values among ζ(3),ζ(5),…,ζ(2s+1)\zeta(3), \zeta(5), \dots, \zeta(2s+1) (such as at least 22 irrational values among ζ(3),ζ(5),ζ(7),ζ(9),ζ(11)\zeta(3), \zeta(5), \zeta(7), \zeta(9), \zeta(11)), yet no known linear-form construction eliminates ζ(7),ζ(9),ζ(11)\zeta(7), \zeta(9), \zeta(11) while keeping denominators small enough to isolate ζ(5)\zeta(5) alone.

Best known results

  • Ball and Rivoal (2001): for odd a≥3a \ge 3, the Q\mathbb{Q}-span of 1,ζ(3),ζ(5),…,ζ(a)1, \zeta(3), \zeta(5), \dots, \zeta(a) has dimension at least 1+o(1)1+ln⁡2ln⁡a\frac{1+o(1)}{1+\ln 2} \ln a.
  • Zudilin (2001): at least one of the four numbers ζ(5),ζ(7),ζ(9),ζ(11)\zeta(5), \zeta(7), \zeta(9), \zeta(11) is irrational.
  • Fischler, Sprang, and Zudilin (2019): among ζ(3),ζ(5),…,ζ(2s+1)\zeta(3), \zeta(5), \dots, \zeta(2s+1), at least 2(1−o(1))ln⁡sln⁡ln⁡s2^{(1-o(1)) \frac{\ln s}{\ln \ln s}} values are irrational.

Tools and where they stop

ToolAchievedWhere it stops
Well-poised hypergeometric series and Nesterenko's linear independence criterion (Ball–Rivoal–Zudilin)Produces small linear forms in 1,ζ(3),ζ(5),…,ζ(2s+1)1, \zeta(3), \zeta(5), \dots, \zeta(2s+1) with controlled common denominators lcm(1,2,…,n)d\mathrm{lcm}(1, 2, \dots, n)^d, proving dimension lower bounds and Zudilin's four-value theoremThe symmetry of the rational functions needed to cancel ζ(2),ζ(4),…\zeta(2), \zeta(4), \dots forces the exponent dd (and hence the denominator growth edne^{dn}) to exceed the analytic decay when only 11 and ζ(5)\zeta(5) are retained
Hankel determinants and holomorphic modular / Padé methods (Apéry–Beukers)Explains Apéry's recurrence for ζ(2)\zeta(2) and ζ(3)\zeta(3) via triple integrals and modular forms of weight 22 and 44For ζ(5)\zeta(5), natural 55-fold Beukers-type integrals have arithmetic denominators lcm(1,…,n)5\mathrm{lcm}(1, \dots, n)^5 that outgrow the geometric convergence rate of the integral

Open questions

  • Is ζ(5)\zeta(5) irrational?
  • Are 1,π,ζ(3),ζ(5),ζ(7),…1, \pi, \zeta(3), \zeta(5), \zeta(7), \dots algebraically independent over Q\mathbb{Q}?

References

  1. Roger Apéry (1979). Irrationalité de ζ(2) et ζ(3)
  2. Keith Ball, Tanguy Rivoal (2001). Irrationalité d'une infinité de valeurs de la fonction zêta aux entiers impairs · DOI:10.1007/s002220100168
  3. Wadim Zudilin (2001). One of the numbers ζ(5), ζ(7), ζ(9), ζ(11) is irrational · DOI:10.1070/RM2001v056n04ABEH000427
  4. Stéphane Fischler, Johannes Sprang, Wadim Zudilin (2019). Many odd zeta values are irrational · DOI:10.1112/S0010437X1900722X · arXiv:1803.08905