Birkhoff ergodic theorem
Statement
Let be a measure-preserving system with a probability measure, and . Then the time averages converge -almost everywhere to a -invariant function with ; if is ergodic, almost everywhere.
Why is it true?
Watching a single trajectory for a very long time and averaging what you see along the way gives, almost always, the same answer as averaging over the whole space at one instant — provided the system does not break into pieces the trajectory cannot mix between. Time spent equals space explored, on average, once the system is ergodic.
Proof sketch
The standard proof uses the maximal ergodic theorem: for and , one shows via a telescoping/maximal-function argument. Applying this to and for rationals on the -invariant set where the of the time averages exceeds and the is below shows that this set has measure zero, forcing almost-everywhere convergence to a limit function ; invariance of follows since shifting by does not change the time average in the limit, and the identity of integrals follows from the dominated convergence theorem applied along a truncation argument.
Topics that use this theorem
Related theorems
Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- Peter Walters (1982). An Introduction to Ergodic Theory