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TheoremProved

Birkhoff ergodic theorem

Statement

Let (X,B,μ,T)(X,\mathcal{B},\mu,T) be a measure-preserving system with μ\mu a probability measure, and f∈L1(μ)f \in L^1(\mu). Then the time averages 1n∑k=0n−1f(Tkx)\frac{1}{n}\sum_{k=0}^{n-1} f(T^k x) converge μ\mu-almost everywhere to a TT-invariant function f∗f^* with ∫f∗ dμ=∫f dμ\int f^* \,d\mu = \int f\,d\mu; if TT is ergodic, f∗=∫f dμf^* = \int f\,d\mu almost everywhere.

Why is it true?

Watching a single trajectory for a very long time and averaging what you see along the way gives, almost always, the same answer as averaging over the whole space at one instant — provided the system does not break into pieces the trajectory cannot mix between. Time spent equals space explored, on average, once the system is ergodic.

Proof sketch

The standard proof uses the maximal ergodic theorem: for f∈L1f \in L^1 and Mf=sup⁡n≥11n∑k=0n−1f∘TkMf = \sup_{n \ge 1} \frac{1}{n}\sum_{k=0}^{n-1} f\circ T^k, one shows ∫{Mf>0}f dμ≥0\int_{\{Mf > 0\}} f\, d\mu \ge 0 via a telescoping/maximal-function argument. Applying this to f−af - a and b−fb - f for rationals a>ba > b on the TT-invariant set where the lim sup⁡\limsup of the time averages exceeds aa and the lim inf⁡\liminf is below bb shows that this set has measure zero, forcing almost-everywhere convergence to a limit function f∗f^*; invariance of f∗f^* follows since shifting by TT does not change the time average in the limit, and the identity of integrals follows from the dominated convergence theorem applied along a truncation argument.

Topics that use this theorem

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Step-by-step proofs

No step-by-step proof yet for this theorem.

References

  1. Peter Walters (1982). An Introduction to Ergodic Theory