Erdős–Szekeres upper bound for Ramsey numbers
Statement
For all integers , the Ramsey number is finite and satisfies . Consequently, .
Why is it true?
Fix a vertex : either its red neighborhood is large enough to force a red or a blue , or else its blue neighborhood is large enough to force a red or a blue .
Proof sketch
**Step 1 (pigeonhole split of the neighborhood of ).** Let and fix a vertex . Partition the remaining vertices into (red edge to ) and (blue edge to ). Since , either or .
Step 2 (inductive conclusion). If , the subgraph on contains a blue or a red that joins to form a red . Symmetrically for .
Step 3 (binomial bound by induction). Base cases and match and . For , Pascal's identity gives .
Topics that use this theorem
Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- Marcelo Campos, Simon Griffiths, Robert Morris, Julian Sahasrabudhe (2023). An exponential improvement for diagonal Ramsey · arXiv:2303.09521
- Sam Mattheus, Jacques Verstraëte (2024). The asymptotics of r(4,t) · DOI:10.4007/annals.2024.199.2.8
- Ronald L. Graham, Bruce L. Rothschild, Joel H. Spencer (1990). Ramsey Theory (2nd ed.)