The Picard–Lindelöf existence-uniqueness theorem
Statement
Suppose is continuous on a rectangle around and satisfies a Lipschitz condition in : for some constant . Then the initial value problem has a unique solution on some interval containing .
Why is it true?
The Lipschitz condition bounds how steeply can vary in the -direction, which prevents nearby solution trajectories from splitting apart or crossing: it is exactly the condition needed to guarantee a well-defined flow, with precisely one trajectory passing through each point.
Proof sketch
Rewriting the initial value problem as an integral equation, a continuous function solves if and only if it solves ; this equivalence follows from the fundamental theorem of calculus.
Define the Picard iteration operator on continuous functions by , restricted to a small interval chosen so that stays in the rectangle where the hypotheses hold.
For two continuous functions on , the Lipschitz condition gives . Choosing small enough that makes a contraction mapping in the supremum norm.
By the Banach fixed-point theorem, a contraction on a complete metric space (the continuous functions on with the supremum norm) has exactly one fixed point , satisfying . This fixed point is precisely the unique solution of the original initial value problem on .
Topics that use this theorem
Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- William E. Boyce, Richard C. DiPrima, Douglas B. Meade (2017). Elementary Differential Equations and Boundary Value Problems
- Morris Tenenbaum, Harry Pollard (1985). Ordinary Differential Equations