Volume and surface area of a sphere (Archimedes)
Statement
A sphere of radius has volume and surface area ; both are equal to of the volume and total surface area of its circumscribing right circular cylinder of radius and height .
Why is it true?
Slice a hemisphere of radius and a right circular cylinder of radius and height with an inverted cone of radius and height hollowed out of it by a horizontal plane at height above the base. By the Pythagorean theorem, the disk cross-section of the hemisphere has radius and area , which is identical to the area of the ring cross-section of the hollowed cylinder. Because every horizontal slice has the same area, the hemisphere has volume , so the full sphere has volume .
Proof sketch
At height , a plane perpendicular to the axis cuts the sphere of radius in a disk of radius and area . Comparing this slice by Cavalieri's principle with a cylinder of radius and height from which two cones of base radius and height have been removed (or integrating ) gives . Partitioning the sphere into thin pyramids of height with bases tiling the surface of area gives , whence .
Stated by
Proved by
Topics that use this theorem
Related theorems
Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- Archimedes (translated by Thomas L. Heath) (1897). The Works of Archimedes (On the Sphere and Cylinder, Book I, Propositions 33–34)
- Reviel Netz, William Noel (2007). The Archimedes Codex