Gauss's Theorema Egregium
Statement
The Gaussian curvature of a smooth surface (the product of its principal curvatures and ) is an intrinsic invariant: it depends only on the first fundamental form and its first and second partial derivatives, and is therefore preserved by every local isometry.
Why is it true?
The individual principal curvatures and describe how a surface bends in surrounding space — rolling a flat sheet of paper () into a cylinder of radius changes them to and without stretching or tearing the paper. Yet their product stays , whereas a sphere of radius has and can never be flattened onto a plane without distorting distances; two-dimensional inhabitants measuring only lengths and angles inside the surface can detect without ever seeing the ambient space .
Proof sketch
For a smooth surface with first fundamental form coefficients and second fundamental form coefficients , the shape operator has determinant . Expressing the third partial derivatives of the position vector via the Gauss equations in terms of the Christoffel symbols (which depend only on and their first derivatives) and using the symmetry expresses entirely in terms of and their first and second derivatives (the Brioschi formula), proving that depends only on the intrinsic metric.
Stated by
Proved by
Topics that use this theorem
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Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- Carl Friedrich Gauss (translated by Peter Pesic) (2005). General Investigations of Curved Surfaces
- Manfredo P. do Carmo (1976). Differential Geometry of Curves and Surfaces