MathLabs

International Mathematical Olympiad · 1960

Problems

  1. Problem 1Determine all three-digit numbers NN that are divisible by 1111, such that N/11N/11 equals the sum of the squares of the digits of NN.Solutions: 2
  2. Problem 2For which real numbers xx does the inequality 4x2(1−1+2x)2<2x+9\dfrac{4x^2}{\left(1-\sqrt{1+2x}\right)^2} < 2x+9 hold?Solutions: 1
  3. Problem 3In a given right triangle ABCABC, the hypotenuse BCBC has length aa and is divided into nn equal parts, where nn is odd. The central part subtends an angle α\alpha at AA. If hh is the perpendicular distance from AA to BCBC, prove that tan⁡α=4nha(n2−1)\tan\alpha=\dfrac{4nh}{a(n^2-1)}.Solutions: 1
  4. Problem 4Construct a triangle ABCABC given the lengths of the altitudes from AA and BB and the length of the median from AA.Solutions: 1
  5. Problem 5The cube ABCDA′B′C′D′ABCDA'B'C'D' has AA above A′A', BB above B′B', and so on. Let XX be any point of the face diagonal ACAC and YY any point of B′D′B'D'. (a) Find the locus of the midpoint of XYXY. (b) Find the locus of the point ZZ on XYXY such that ZY=2XZZY=2XZ.Solutions: 1
  6. Problem 6A cone of revolution has an inscribed sphere tangent to its base and sloping surface. A cylinder is circumscribed about the sphere, with its base in the base of the cone. If the volumes of the cone and cylinder are V1V_1 and V2V_2, respectively: (a) prove that V1≠V2V_1\ne V_2; (b) find the smallest possible value of V1/V2V_1/V_2, and in this case construct the half-angle of the cone.Solutions: 1
  7. Problem 7In the isosceles trapezoid ABCDABCD with AB∥DCAB\parallel DC and BC=ADBC=AD, let AB=aAB=a, CD=cCD=c, and let the perpendicular distance from AA to CDCD be hh. Show how to construct all points XX on the axis of symmetry such that ∠BXC=∠AXD=90∘\angle BXC=\angle AXD=90^\circ. Find the distance of each such XX from ABAB and from CDCD, and give the condition for such points to exist.Solutions: 1