MathLabs

Problem 2

For which real numbers xx does the inequality 4x2(1−1+2x)2<2x+9\dfrac{4x^2}{\left(1-\sqrt{1+2x}\right)^2} < 2x+9 hold?
Step 1 of 5: Domain restrictions from the square root and the denominator
In plain words

Before touching the inequality itself, pin down exactly which xx even make sense to plug in — a square root and a denominator each forbid part of the real line.

1+2x≥0 and 1+2x≠11+2x\ge 0 \text{ and } \sqrt{1+2x}\neq 1
Detailed analysis

The square root 1+2x\sqrt{1+2x} is only real when 1+2x≥01+2x\ge0, i.e. x≥−12x\ge-\tfrac12. The denominator (1−1+2x)2\left(1-\sqrt{1+2x}\right)^2 must also be nonzero, i.e. 1+2x≠1\sqrt{1+2x}\neq1, i.e. 1+2x≠11+2x\neq1, i.e. x≠0x\neq0. These are exactly the values of xx for which the left-hand side is even defined.