MathLabs

Problem 5

The cube ABCDA′B′C′D′ABCDA'B'C'D' has AA above A′A', BB above B′B', and so on. Let XX be any point of the face diagonal ACAC and YY any point of B′D′B'D'. (a) Find the locus of the midpoint of XYXY. (b) Find the locus of the point ZZ on XYXY such that ZY=2XZZY=2XZ.
Step 3 of 5: Find the midpoint locus
M=X+Y2=(t+1−s2,t+s2,12)M=\dfrac{X+Y}{2}=\left(\dfrac{t+1-s}{2},\dfrac{t+s}{2},\dfrac12\right)
Detailed analysis

The midpoint MM always has z=1/2z=1/2. Its other coordinates are affine in t,st,s. More revealingly, Mx+My=1/2+tM_x+M_y=1/2+t ranges over [1/2,3/2][1/2,3/2], while Mx−My=1/2−sM_x-M_y=1/2-s ranges over [−1/2,1/2][-1/2,1/2]. Thus MM fills a square in the mid-plane, with side length 1/21/\sqrt2, whose vertices are the midpoints of the four vertical faces.