MathLabs

Problem 5

The cube ABCDA′B′C′D′ABCDA'B'C'D' has AA above A′A', BB above B′B', and so on. Let XX be any point of the face diagonal ACAC and YY any point of B′D′B'D'. (a) Find the locus of the midpoint of XYXY. (b) Find the locus of the point ZZ on XYXY such that ZY=2XZZY=2XZ.
Step 5 of 5: Identify the rectangle and its dimensions
Zx+Zy=4t+13,Zx−Zy=1−2s3Z_x+Z_y=\dfrac{4t+1}{3},\quad Z_x-Z_y=\dfrac{1-2s}{3}
Detailed analysis

Now Zx+ZyZ_x+Z_y ranges over [1/3,5/3][1/3,5/3] and Zx−ZyZ_x-Z_y over [−1/3,1/3][-1/3,1/3]. The two parameter directions are perpendicular, with lengths 22/32\sqrt2/3 and 2/3\sqrt2/3. Thus the locus is a filled rectangle in z=2/3z=2/3, of dimensions 22/3×2/32\sqrt2/3\times\sqrt2/3.