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Problem 5
Problem 5
Does there exist a positive integer
n
n
n
such that
n
n
n
has exactly
2000
2000
2000
distinct prime divisors and
n
n
n
divides
2
n
+
1
2^n+1
2
n
+
1
?
Step 1 of 5: Base case
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9
∣
2
9
+
1.
9\mid2^9+1.
9
∣
2
9
+
1.
Detailed analysis
The number 9 has one distinct prime divisor.
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