MathLabs

Squaring the circle

Solved, 1882GeometryAlgebra
Statement

Using only a compass and an unmarked straightedge, construct in finitely many steps a square whose area equals the area of a given circle.

Squaring a circle of radius 1 by compass and straightedge would require constructing a segment of length π\sqrt{\pi}, and Pierre Wantzel had shown in 1837 that every length constructible this way is an algebraic number obtained by a tower of square roots — in particular, algebraic of degree a power of 2. Ferdinand von Lindemann closed the problem in 1882 by proving that π\pi itself is transcendental (not a root of any nonzero polynomial with rational coefficients), adapting the method Charles Hermite had used in 1873 to prove ee transcendental. Since π\pi is transcendental, so is π\sqrt{\pi}, and no compass-and-straightedge construction can produce it.

  1. Lindemann's transcendence proof of π\pi settles squaring the circle (1882)Ferdinand von Lindemann, 1882Difficulty 4/5Advanced

References

  1. Ferdinand von Lindemann (1882). Über die Zahl π
  2. Pierre Laurent Wantzel (1837). Recherches sur les moyens de reconnaître si un problème de géométrie peut se résoudre avec la règle et le compas
  3. Petr Beckmann (1971). A History of Pi