MathLabs

Worked solution: The polynomial method resolves the cap set problem (Croot-Lev-Pach, Ellenberg-Gijswijt, 2016)

Step 1 of 7: The cap set problem: how big can a progression-free set be?
In plain words

Think of the game SET, played on cards described by nn ternary features: a cap set is a collection of cards with no three that form a legal "set" (the pattern that is forbidden is exactly a 3-term arithmetic progression x+y+z=0x+y+z=0 in F3n\mathbb{F}_3^n). For decades the best known upper and lower bounds on the largest possible cap set were painfully far apart, leaving open whether cap sets could occupy almost all of F3n\mathbb{F}_3^n or only an exponentially tiny sliver of it.

A⊆F3n, ∄ x,y,z∈A distinct with x+y+z=0  ⟹  ∣A∣≤O(cn), c<3A \subseteq \mathbb{F}_3^n,\ \nexists\, x,y,z \in A \text{ distinct with } x+y+z=0 \implies |A| \le O(c^n),\ c < 3
Detailed analysis

Ellenberg and Gijswijt (2017, Introduction) study subsets AA of F3n\mathbb{F}_3^n that contain no three-term arithmetic progression, i.e. no distinct x,y,z∈Ax,y,z \in A with x+y+z=0x+y+z=0; the maximal size of such a set is denoted r3(F3n)r_3(\mathbb{F}_3^n). The trivial bound is ∣A∣≤3n|A| \le 3^n, and the best previous upper bound, due to Bateman and Katz (2012), was only O(3n/n1+ϵ)O(3^n / n^{1+\epsilon}) -- barely better than trivial, while the best lower-bound constructions gave sets of size around 2.2n2.2^n. The paper resolves the long-standing question of the exponential growth rate: it proves ∣A∣≤O(cn)|A| \le O(c^n) for an explicit constant c≈2.756c \approx 2.756, strictly less than 33.

Terms in this step
Cap set
A subset AA of F3n\mathbb{F}_3^n containing no three distinct points x,y,zx,y,z with x+y+z=0x+y+z=0, i.e. no non-trivial three-term arithmetic progression.
Three-term arithmetic progression
Three elements x,y,zx,y,z with yy the average of xx and zz; over F3\mathbb{F}_3 this is exactly the equation x+y+z=0x+y+z=0.
Knowledge used in this step