Divergence theorem (Gauss–Ostrogradsky theorem)
Statement
Let be a bounded region with smooth boundary oriented by the outward normal , and let be a continuously differentiable vector field on a neighborhood of . Then .
Why is it true?
The divergence measures how much a vector field spreads out from each point, like the net rate fluid is created or destroyed there. Adding up all that local creation inside a region must equal the net flow escaping through its boundary — nothing is lost in between, it just has to leave through the surface.
Proof sketch
Prove the theorem first for a rectangular box by applying the fundamental theorem of calculus to each coordinate direction, so that each pair of opposite faces contributes the flux difference matching . Extend to a general elementary region (bounded above and below by graphs over each axis) using the same one-variable argument component by component, then cover a general region with a union of such elementary pieces and sum, noting that fluxes through shared interior faces cancel, leaving exactly the flux through the outer boundary.
Stated by
Topics that use this theorem
Related theorems
Step-by-step proofs
No step-by-step proof yet for this theorem.
References
- Jerrold E. Marsden, Anthony J. Tromba (2003). Vector Calculus