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Divergence theorem (Gauss–Ostrogradsky theorem)

Statement

Let V⊂R3V \subset \mathbb{R}^3 be a bounded region with smooth boundary ∂V\partial V oriented by the outward normal n\mathbf{n}, and let F\mathbf{F} be a continuously differentiable vector field on a neighborhood of V‾\overline{V}. Then ∭V(∇⋅F) dV=∬∂VF⋅n dS\iiint_V (\nabla \cdot \mathbf{F})\, dV = \iint_{\partial V} \mathbf{F} \cdot \mathbf{n}\, dS.

Why is it true?

The divergence ∇⋅F\nabla \cdot \mathbf{F} measures how much a vector field spreads out from each point, like the net rate fluid is created or destroyed there. Adding up all that local creation inside a region must equal the net flow escaping through its boundary — nothing is lost in between, it just has to leave through the surface.

Proof sketch

Prove the theorem first for a rectangular box by applying the fundamental theorem of calculus to each coordinate direction, so that each pair of opposite faces contributes the flux difference matching ∂Fi/∂xi\partial F_i/\partial x_i. Extend to a general elementary region (bounded above and below by graphs over each axis) using the same one-variable argument component by component, then cover a general region with a union of such elementary pieces and sum, noting that fluxes through shared interior faces cancel, leaving exactly the flux through the outer boundary.

Stated by

Topics that use this theorem

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Step-by-step proofs

No step-by-step proof yet for this theorem.

References

  1. Jerrold E. Marsden, Anthony J. Tromba (2003). Vector Calculus