MathLabs
TheoremProved

Cross-multiplication test for equal fractions

Statement

For integers a,ca,c and nonzero integers b,db,d: ab=cd\dfrac{a}{b}=\dfrac{c}{d} if and only if ad=bcad=bc.

Why is it true?

Comparing two fractions directly is awkward because they may be written with different denominators; multiplying through by both denominators clears the fractions and turns the comparison into an ordinary integer equation.

Proof sketch

Direction 1 (⇒\Rightarrow). Suppose ab=cd\dfrac{a}{b}=\dfrac{c}{d}. Since b,d≠0b,d\neq0, we may multiply both sides by the nonzero number bdbd: ab⋅bd=cd⋅bd\frac{a}{b}\cdot bd = \frac{c}{d}\cdot bd. On the left, ab⋅bd=a⋅d\frac{a}{b}\cdot bd = a\cdot d because the factor bb cancels; on the right, cd⋅bd=c⋅b\frac{c}{d}\cdot bd = c\cdot b because the factor dd cancels. So ad=bcad=bc.

Direction 2 (⇐\Leftarrow). Suppose ad=bcad=bc. Divide both sides by the nonzero number bdbd: adbd=bcbd\dfrac{ad}{bd}=\dfrac{bc}{bd}. Cancel the common factor dd from the left fraction and the common factor bb from the right fraction: ab=cd\dfrac{a}{b}=\dfrac{c}{d}.

Both directions hold, so the two statements are equivalent: ab=cd\dfrac{a}{b}=\dfrac{c}{d} exactly when ad=bcad=bc.

Topics that use this theorem

Step-by-step proofs

No step-by-step proof yet for this theorem.

References

  1. David M. Burton (2010). Elementary Number Theory
  2. John H. Conway, Richard K. Guy (1996). The Book of Numbers · DOI:10.1007/978-1-4612-4072-3