MathLabs

Worked solution: Euler's proof via the sine product formula (1734–1735)

Step 1 of 6: The target sum and Euler's idea
In plain words

Imagine adding 11 plus 14\frac{1}{4} plus 19\frac{1}{9} plus 116\frac{1}{16} and so on forever: the terms shrink fast, so the total settles on one fixed number, yet nobody could name that number for almost a century. Euler's trick was to sneak up on the very same number from a completely different direction — through the trigonometric function sin⁡x\sin x — and read off its value by comparing two different descriptions of the same object.

ζ(2)=∑n=1∞1n2=1+14+19+116+⋯\zeta(2)=\sum_{n=1}^{\infty}\frac{1}{n^2}=1+\frac{1}{4}+\frac{1}{9}+\frac{1}{16}+\cdots
Detailed analysis

The Basel problem asks for the exact value of this sum, known numerically since the 1600s but with no closed form. Euler's idea was to find a second formula for the same number from the Maclaurin series of sin⁡x\sin x, then match it to a completely different-looking product built from the zeros of sin⁡x\sin x.

Terms in this step
ζ(2)\zeta(2)
Standard shorthand for this particular infinite sum: the value at 22 of the Riemann zeta function ζ(s)=∑n=1∞1/ns\zeta(s)=\sum_{n=1}^\infty 1/n^s.
Closed form
An expression built from a finite number of familiar constants and operations, such as π2/6\pi^2/6, as opposed to an infinite, unevaluated process.
Knowledge used in this step