MathLabs

Squaring the circle

Solved, 1882GeometryAlgebra
Statement

Using only a compass and an unmarked straightedge, construct in finitely many steps a square whose area equals the area of a given circle.

Squaring a circle of radius 1 by compass and straightedge would require constructing a segment of length π\sqrt{\pi}, and Pierre Wantzel had shown in 1837 that every length constructible this way is an algebraic number obtained by a tower of square roots — in particular, algebraic of degree a power of 2. Ferdinand von Lindemann closed the problem in 1882 by proving that π\pi itself is transcendental (not a root of any nonzero polynomial with rational coefficients), adapting the method Charles Hermite had used in 1873 to prove ee transcendental. Since π\pi is transcendental, so is π\sqrt{\pi}, and no compass-and-straightedge construction can produce it.

Wantzel's same algebraic framework simultaneously settled the other two classical problems: doubling the cube (impossible, since 23\sqrt[3]{2} has degree 3, not a power of 2) and trisecting an arbitrary angle (impossible in general, since it would require solving a cubic). All three become possible if the tools are extended — for instance, with a marked ruler (neusis constructions) or by allowing origami folds (which can solve cubics) — and approximate quadratures of the circle accurate to many decimal places, such as those found by Ramanujan, remain popular constructions even though no exact one can exist.

References

  1. Ferdinand von Lindemann (1882). Über die Zahl π
  2. Pierre Laurent Wantzel (1837). Recherches sur les moyens de reconnaître si un problème de géométrie peut se résoudre avec la règle et le compas
  3. Petr Beckmann (1971). A History of Pi