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Euler's polyhedron formula

Statement

For any convex polyhedron with VV vertices, EE edges, and FF faces, V−E+F=2V - E + F = 2.

Why is it true?

Flatten a polyhedron's surface onto a plane (remove one face and stretch the rest flat) to get a connected planar graph; V - E + F stays the same no matter how you build up or simplify that graph, because adding a vertex on an edge, or an edge splitting a face, changes two of the three counts by +1 and -1 at once.

Proof sketch

Project the polyhedron's edges onto a sphere around an interior point, then puncture the sphere through the interior of one face and flatten it into a planar graph. Triangulate every non-triangular face by adding diagonals (each diagonal adds one edge and one face, leaving V - E + F unchanged), then repeatedly remove an outer edge shared by two triangles - this removes either one edge and one face, or one vertex, two edges and one face, again preserving V - E + F. The process ends with a single triangle, for which V - E + F = 3 - 3 + 1 = 1; adding back the removed face gives V - E + F = 2.

Stated by

Proved by

Topics that use this theorem

Related theorems

Step-by-step proofs

References

  1. David S. Richeson (2008). Euler's Gem: The Polyhedron Formula and the Birth of Topology
  2. Augustin-Louis Cauchy (1813). Recherches sur les polyèdres — première partie