MathLabs
Step 5 of 6: Conclude that V − E + F = 2 for the original polyhedron
In plain words

Think of V−E+FV-E+F as a chip on a gaming table that nobody is allowed to touch: every move in the game (flattening, cutting a diagonal, peeling a triangle) leaves the chip exactly where it was. Once the game ends with a single triangle and a visible chip value of 22, that must have been its value from the very first move.

V−E+F=2V - E + F = 2
Detailed analysis

Every operation used along the way — flattening, triangulating, and removing triangles — left V−E+FV - E + F unchanged, and the final graph gives V−E+F=2V - E + F = 2. Since the quantity never changed during the reduction, it must already have equalled 22 for the flattened graph, and hence for the original convex polyhedron.

Terms in this step
Invariant
A quantity that stays exactly the same throughout a sequence of operations, even though the object it is computed from keeps changing.
Knowledge used in this step