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Worked solution: The three-dimensional case: every Kakeya set in $\mathbb{R}^3$ has dimension 3 (Wang–Zahl, 2025)

Step 5 of 5: Closing the induction: thick prisms and thin prisms
In plain words

What remains is exactly the case where grains do not rescale into a Kakeya-like configuration — they instead pile up far too densely ('super-Kakeya') inside some larger convex prism WW of unspecified dimensions. Wang and Zahl split on whether WW is 'thick' (every side length ≫δ\gg\delta) or 'thin' (thickness ≈δ\approx\delta). If WW is thick, a delicate further induction-on-scales argument shows that K(d)K(d) upgrades to an 'x-ray' estimate strong enough to exhibit the Frostman violation of Step 3 directly. If WW is thin, the classical planar L2L^2 argument together with the super-Kakeya density of grains forces EE to nearly fill up WW entirely — but then WW itself could have been taken as an even larger grain in Step 4, contradicting the maximality with which the grains were originally chosen. Every configuration therefore falls into a case that closes the induction, completing the proof that K(3−ε)K(3-\varepsilon) holds for every ε>0\varepsilon>0, i.e. every Kakeya set in R3\mathbb{R}^3 has Hausdorff and Minkowski dimension exactly 33.

W=convex prism containing a ‘super-Kakeya’ bundle of grains;thick (min⁡dim⁡W≫δ) vs. thin (min⁡dim⁡W≈δ)W = \text{convex prism containing a `super-Kakeya' bundle of grains}; \qquad \text{thick } (\min\dim W \gg \delta) \ \text{vs.}\ \text{thin } (\min\dim W \approx \delta)
Detailed analysis

This case split (Wang–Zahl 2025, §§6–8, following the outline in Tao's blog exposition) is where the bulk of the 127 pages lives. For thick prisms WW, the authors prove an 'x-ray estimate' — a variant of K(d)K(d) that bounds not just the total volume of a tube union but how it intersects every affine plane, strong enough that a super-Kakeya bundle of grains inside WW directly forces the Frostman violation of Step 3. For thin prisms, an elementary planar L2L^2 argument (structurally the same computation as Step 3 of the R2\mathbb{R}^2 proof, applied inside WW's near-planar cross-section) combined with the super-Kakeya count shows ∣E∩W∣≳∣W∣1−o(1)|E\cap W|\gtrsim |W|^{1-o(1)}, so EE nearly fills WW; since WW was assumed larger than the maximal grain size fixed in Step 3, this contradicts that maximality and rules the case out. No configuration escapes both alternatives, which completes the induction on scales and the proof of K(3−ε)K(3-\varepsilon) for every ε>0\varepsilon>0.