使用 pairing lemma
Pair terms symmetrically. The recurrence shows f(j)+f(2r+1−j) f(j)+f(2r+1-j)f(j)+f(2r+1−j) 是nonincreasing as j j j 移动s 从 111 到 r r r, so 每个pair 是在least f(r)+f(r)=2f(r) f(r)+f(r)=2f(r)f(r)+f(r)=2f(r). Th是proves lemma.