Find initial identities
译文:Putting m=n=0 m=n=0m=n=0 译文: gives f(f(0))=f(f(0))+f(0) f(f(0))=f(f(0))+f(0)f(f(0))=f(f(0))+f(0) 译文:, so f(0)=0 f(0)=0f(0)=0 译文:. Putting m=0 m=0m=0 译文: then gives f(f(n))=f(n) f(f(n))=f(n)f(f(n))=f(n) 对每个 n n n, 且equati上becomes f(m+f(n))=f(m)+f(n) f(m+f(n))=f(m)+f(n)f(m+f(n))=f(m)+f(n).